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3v^2-19v-72=0
a = 3; b = -19; c = -72;
Δ = b2-4ac
Δ = -192-4·3·(-72)
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1225}=35$$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-19)-35}{2*3}=\frac{-16}{6} =-2+2/3 $$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-19)+35}{2*3}=\frac{54}{6} =9 $
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